3x/x^2-4-1/x^2

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Solution for 3x/x^2-4-1/x^2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x)/(x^2)-(1/(x^2))-4 = 0

(3*x)/(x^2)-x^-2-4 = 0

3*x^-1-x^-2-4 = 0

t_1 = x^-1

3*t_1^1-1*t_1^2-4 = 0

3*t_1-t_1^2-4 = 0

DELTA = 3^2-(-4*(-1)*4)

DELTA = -7

DELTA < 0

x belongs to the empty set

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